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For my Science fiction and Fantasy genre book, I need an energy source whose energy output should be much more than even a fully functional Dyson sphere. Can you please suggest some hypothetical concept as an option?

Edit: I need just a Supernovae of energy to make some kind of hypothetical weapon, I don't need continuous source of energy. Moreover, I mentioned Dyson sphere just to indicate that I want to harness very high amount of energy.

Arpit
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    2 Dyson spheres around a pair of binary stars! – Henry Taylor Oct 18 '18 at 15:03
  • Can you please suggest some other alternative whose energy output could be much higher, like equivalent to thousands or millions of Dyson sphere – Arpit Oct 18 '18 at 15:05
  • Arpit, Henry Taylor probably did not see your response. For more information, see this post on how to use @mentions – John Locke Oct 18 '18 at 15:19
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    What are you looking for, higher total energy, higher power (rate that energy is produced), or higher energy efficiency (energy produced vs. energy wasted) – Cort Ammon Oct 18 '18 at 15:22
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    Do you need a stable process, or just a short burst (like a supernova) of energy? – Alexander Oct 18 '18 at 17:50
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    What are you going to do with such an ungodly amount of energy? I have a feeling that you might be overdoing it a bit. The scale of a Dyson sphere (stellar energy output) is already incredible and likely immersion-breaking. – Chieron Oct 18 '18 at 18:26
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    A star is the energy source for a Dyson Sphere. The Dyson Sphere uses the star's energy. It appears you are asking for something that produces more energy than the most energetic star but it would help if you clarified that in the question. – Tracy Cramer Oct 18 '18 at 18:49
  • Do you want it to be on the same scale as a Dyson sphere? Or would a smaller but more efficient power source work? For example, a reactor that would produce more energy than a Dyson sphere if you packed a Dyson sphere with those reactors, but typically they'd be built small enough to power a single home? – Rob Watts Oct 18 '18 at 19:28
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    @TracyCramer Absolutely right! Good to see someone else realized that point. Dyson spheres aren't themselves generators of energy. My guess is the OP wants a more energetic source to power a Dyson sphere. But it does need clarifying. – a4android Oct 19 '18 at 04:17
  • This Slow Teleportation device could be adapted to produce energy, scaled up I don't see why it couldn't produce near infinite energy. – aslum Oct 18 '18 at 19:13
  • That'd right, Dyson spheres are powered by the star they're built around. Actually they have a huge energy management problem - all the energy radiated by the star must be disposed of somehow i.e. Ejecting it overboard, or the sphere would just keep heating up. – Harper - Reinstate Monica Oct 20 '18 at 17:44
  • @Harper - "traditionally" you drive a heat engine with the temperature difference between the inside and outside of the Dyson sphere. The outside of your sphere is a black-body radiator; the input temperature is the effective temperature of the star (give or take). – TLW Oct 20 '18 at 19:49
  • If you need a quick burst of supernova-scale energy for your weapon, your best bet is likely to be "a supernova" (assuming that you can trigger one artificially and deal with the side-effects, but you'll have a similar problem with anything else generating that much energy). – user3482749 Mar 14 '20 at 02:05

13 Answers13

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I think @nzaman had the right idea- black holes contain an enormous amount of energy, in the form of angular momentum. However, you don't need turbines to harness the energy. As explained by this video, an object that escapes the ergosphere by giving up some of its mass will speed up.

The amount that the object speeds up is even more than the mass that the object gives up. This is called the Penrose Process. Here is a screenshot from the video that nicely illustrates the process:

screenshot

The object enters the black hole's ergosphere and then shoots out, accelerating as it does.

There is also another way to harvest energy from the black hole, and it doesn't involve giving up mass. Shining a laser by a black hole has the same effect. In the process of superradiant scattering, we can use mirrors to make the laser reflect through the black hole's ergosphere over and over. The light continually amplifies, until it is strong enough to be emitted and used as a power source. If the light isn't emitted, it has the potential to create possibly the most destructive weapon in the entire universe. Called the Black Hole Bomb, the light will eventually break free of the mirrors and wreak who-knows-what havoc.

screenshot

Logan R. Kearsley
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John Locke
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    You can't escape from the event horizon. It's the ergosphere that you're escaping from. – Acccumulation Oct 18 '18 at 15:52
  • @Acccumulation Thanks for the heads up, I'll fix that. – John Locke Oct 18 '18 at 19:07
  • Ok, just realized you already did. Thanks. – John Locke Oct 18 '18 at 19:07
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    Think that you've just written the basis for the next Star Wars film's super weapon. – Escaped dental patient. Oct 18 '18 at 20:27
  • This specific video was the first thing I thought of when I saw this question. It's a great solution. – Andon Oct 18 '18 at 20:35
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    @Duck It's too hard science for Star Wars. It has to be much more foreign to us. What if this is somehow proved wrong in the next decade? How do you think Star Wars fans will feel? They will feel let down and disillusioned by the film. Another problem is that the films also seem to have sperate laws of physics. As we know, that happened a long time ago in a galaxy far away, and The Force has since dissipated as cosmic background radiation... – John Locke Oct 18 '18 at 20:43
  • ...Also, having black hole bombs back then breaks all of the rules of weapons in ancient alien civilizations. I am actually surprised I was able to find a source for that. – John Locke Oct 18 '18 at 20:44
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    @Andon I saw this video a while back on an answer, and it is a great way to explain black hole energy because it's simple and explores all of the possibilities of BH energy harvesting. We should have a meta post with the link to the video and a description of the possibilities it has to link to whenever anyone asks about energy or weapons in space-fairing civilizations. – John Locke Oct 18 '18 at 20:55
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    How much would you have to be throwing at the black hole to make it produce more usable energy than an entire star? – Michael W. Oct 18 '18 at 22:50
  • @MichaelW. I don't know how much energy it will create, I don't profess to know all of the hard science and numbers behind it. The Black Hole Bomb Wikipedia page says "The growth of the field is asserted to be exponential and unstable". They don't go into specifics. You can try checking the references sections in the Wikipedia pages I linked to, or you could ask about it on this site.You can also do a google scholar search for articles on superradiant scattering – John Locke Oct 18 '18 at 23:02
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    Laser's won't work. "An additional condition which must be met is that the field must have a rest mass different from zero." Photons have zero rest mass. –  Oct 19 '18 at 23:37
  • @aidan The Wikipedia page on invariant mass (rest mass) says "Systems whose four-momentum is a null vector (for example a single photon or many photons moving in exactly the same direction) have zero invariant mass, and are referred to as massless". So a laser won't work, but a normal light source that scatters light (like an incandescent light bulb) will work, right? – John Locke Oct 20 '18 at 02:15
  • @JohnLocke No. Not really. Even from a scattered light source, if you go far enough away it is still a single direction light source. My field isn't QFT so I could be wrong, but light in general is just mass less. Mass comes from interaction with the Higgs field (?) and each photon is just an excitation of the EM field. Since you can represent the EM field with many different coordinate systems, a "photon" in one system could be multiple in another. –  Oct 21 '18 at 00:09
  • @aidan I don't know either, I am certainly not a physics expert. It's probably one of those things that you can handwave without upsetting many people because it's so impossible to actually test yet. – John Locke Oct 21 '18 at 01:52
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A bigger Dyson sphere

You can build a Dyson sphere around a galaxy. Or around TON 618, one of the shiniest quasars known:

The surrounding galaxy is not visible from Earth, because the quasar itself outshines it. With an absolute magnitude of −30.7, it shines with a luminosity of 4×1040 watts, or as brilliantly as 140 trillion Suns, making it one of the brightest objects in the Universe.

Compared to an hypothetical Dyson sphere built around our sun, the TON 618 one would give way more than the output you mentioned in the comments to your question.

The Square-Cube Law
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    I was going to write an answer about how you could use a supernova to generate more power. They output about 1 foe ($10^{44} J$) over 20ish days. Over 20 days, TON 618 outputs 200 foe! That's insane! That quasar literally outshines supernovae! – Cort Ammon Oct 18 '18 at 15:33
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    Also, relevant XKCD. The hardware to manage more power output than a supernova itself is going to be a non-trivial piece of handwavium itself! – Cort Ammon Oct 18 '18 at 15:34
  • @CortAmmon that What If is my very favorite one :) – The Square-Cube Law Oct 18 '18 at 15:36
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    ... so bright it outshines supernovae by a factor of 200, yet so far away that it's too dim to see with the naked eye by a good margin. Every time I think I have no sense of scale in the universe, the universe kicks my knees out from underneath me and points out that I don't even have a solid concept of what having no sense of scale might be like. I need a new scale for my bafflement at what the universe has in store! – Cort Ammon Oct 18 '18 at 15:49
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Black holes hypothetically can be tapped to generate the energy of a star in a much (much) smaller package.

Black holes have a number of ways you can extract energy from them. Small black holes (perhaps artificial ones) can be made in size ranges which allow them to emit Hawking radiation. This website has a calculator which allows you to determine how much hawking radiation you can receive from any size of black hole. In this epoch, the cosmic background radiation is high enough that stellar mass black holes are effectively "dark" in terms of Hawking radiation.

enter image description here

The process by which Hawking radiation is emitted

Roger Penrose proposed a method of tapping rotational energy from stellar mass black holes.

The maximum amount of energy gain possible for a single particle via this process is 20.7%.4 The process obeys the laws of black hole mechanics. A consequence of these laws is that if the process is performed repeatedly, the black hole can eventually lose all of its angular momentum, becoming non-rotating, i.e. a Schwarzschild black hole. In this case the theoretical maximum energy that can be extracted from a black hole is 29% its original mass.5 Larger efficiencies are possible for charged rotating black holes.6

enter image description here

Simplified diagram of the Penrose Process

enter image description here

Another diagram

Since we are talking about stellar sized black holes, this is actually an enormous amount of energy.

Finally, a refinement of the Penrose process can be made by integrating the electrical and magnetic fields that often accompany the environment surrounding a black hole. This is the Blandford–Znajek process

The Blandford–Znajek requires an accretion disc with a strong poloidal magnetic field around a spinning black hole. The magnetic field extracts spin energy and the power can be estimated as the energy density at the speed of light cylinder times area:

enter image description here

where B is the magnetic field strength, r_c the speed of light radius and ω the angular velocity.6

enter image description here

Quasars are powered by supermassive black holes, with masses thousands to millions of times greater than the Sun

So the energy output will vary based on the size of the black hole being harvested (much like a Dyson sphere output will depend on the star within), but black holes are quite compact, so the energy density will be far higher. Remember, outside of so called "quantum" black holes created artificially or near the beginning of the Universe, black holes are stellar remnants, so you are dealing with objects starting at about 3 solar masses in terms of size, and the black holes near the centres of most galaxies are thousands to millions of times more massive than our Sun.

Thucydides
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  • Could you rewrite the equation in mathjax? That would make it accessible to people using screen readers. – Orphevs Oct 21 '18 at 09:13
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You've not got the "reality-check" tag on this one, so how about...

Vacuum Energy

This is high-octane handwavium. It's almost certainly nonsense, but so is readily harnessing power on the scales you're talking about, so let's roll with it. Vacuum energy is one of the theories behind the energy deficit between observable space and the rate of universal expansion. Its potential scale varies by theoretician from very small (the most likely case) to enormous (the most useful case) to infinite (unlikely, but even more useful for your world).

Now, harvesting the energy responsible for the expansion of the universe might have some localized (or not-so-localized) effects on spacetime, but that could be another fun plot point:

"Preserve the universe!" the activists cried, their placards waving outside the administration building. Inside, the C-suite scoffed. Redshifting of the local cluster had been only 1.4% over the last decade, nothing to worry about.

Assuming you set your reality's version of vacuum energy to the "infinite" or "near-infinite" end of the scale, you can have as much power as you want.

jdunlop
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  • Actually, even at the small end of the scale there is a tremendous amount of vacuum energy. With the most conservative figures, the space in a 1 light year radius from the sun contains same amount of (vacuum) energy as the sun releases in 300,000 years. – Michael Oct 19 '18 at 16:24
  • True, but extracting the energy in a light year radius (and the speed at which you do so) is the larger concern for the OP's question. The job's easier if there's more there to work with. (All theoretically, of course, since no one has been able to prove the existence of, let alone make use of, vacuum energy.) – jdunlop Oct 19 '18 at 17:46
  • Well, the fastest you can do it (unless you have FTL) is in one year, for 300k years worth of solar energy. So it's up to 300,000x the power of a Dyson sphere. Of course, doing it that fast might cause other issues like false vacuum collapse... ;-) – Michael Oct 19 '18 at 18:05
  • ZPMs (Zero-Point Modules) from Stargate use this, but go a step further: They pull the vacuum energy from an artificial pocket dimension so as not to affect our universe. – Izkata Oct 19 '18 at 19:40
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The idea of a Dyson sphere is to capture all the energy produced by a star, at the rate (i.e., power) the star normally emits that energy. Which might take billions of years. One way to get more power out of it (energy per unit of time) would be if you could accelerate the burning of the star.

I guess this is what was seen in The Force Awakens, where the bad guys had a weapon that consumed a star and almost instantaneously turned it into blaster beams or something.

Somewhat more "realistically", you might have something shaped like a Dyson sphere that surrounds a star and consumes it (converting all matter into energy) in a much shorter timespan than the normal life of the star. Then you could go looking for another star to consume, and so on.

workerjoe
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    But you'd get more power that way, and the question specifically asks for energy. – nzaman Oct 18 '18 at 15:44
  • Thanks for the tip. High school physics was > 20 years ago... – workerjoe Oct 18 '18 at 17:23
  • IMO the questioner really isn't clear when they say "energy output should be much more", about whether they mean total energy output in undetermined amount of time, or if they mean rate of energy output in specific amount of time. – Beanluc Oct 18 '18 at 21:06
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If you don't need continuous output, a gamma ray burst https://en.wikipedia.org/wiki/Gamma-ray_burst will do nicely, typically releasings as much energy in a few seconds as the Sun will in its entire 10-billion-year lifetime.

jamesqf
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  • As was pointed out in comments on Joe's answer, this produces a lot more power, but not more energy, which is what the OP is asking for. – jdunlop Oct 18 '18 at 21:55
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    @jdunlop: I'm not sure that what the OP is asking for is just energy output rather than power. – jamesqf Oct 19 '18 at 03:21
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The problem with naturally occurring stars is that, like most things in nature, they aren't purpose built to maximize efficiency.

Sure, they're free to construct, but they come pre-loaded with a bunch of mass that you don't want. It sits in-between your sphere and the energy released by the fusion reaction, preventing clean, unobstructed propagation.

What you really want is a star sized cluster of smaller dyson spheres built around artifical stars, complete with fuel injection and spent mass extraction, so that more of your mass and space are dedicated to the production and storage of energy, instead of an incidental fusion reactor sitting underneath a giant pile of inert mass.

Iron Gremlin
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E=MC2

I'm in the middle of the non-fiction book "Life 3.0" by Max Tegmark. I don't remember the numbers exactly, but he discusses the fact that only a tiny fraction of a star's energy is actually radiated as light or heat — less than 1% of its total energy. The book is about possible scenarios and directions for artificial intelligence, so he is (probably appropriately) diving off the deep end, but I believe he was suggesting that mass itself is equivalent and could be converted to energy (E=MC2). So in some futuristic scenario, any kind of mass could be converted to a lot of energy. And you could potentially harvest an entire star, or solar system, or galaxy. Preferably not ours.

colllin
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Here is a radical option inspired by Stephen Baxter's book Ultima: time travel from the end of the universe. If your universe will end by a big rip or by M-Brane collision, there could be massive amounts of energy released as the universe rips apart.

More possible method: the smaller a blackhole is, the faster it evaporates and outputs hawking radiation. By producing millions of microscopic black holes(via focusing lasers on a very small space to create a kugelblitz) and continually feeding each one a trickle of matter, you could convert matter to energy with 100% efficiency.

qazwsx
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Black holes at the centre of galaxies.

Collect energy by placing a series of giant turbines just outside the accretion disk, or even in it, to be driven by the rotating matter.
If you could somehow couple them to form a tight circle, it would both neutralise the gravity well of the black hole, as well as create another plane of rotation which you can tap for energy.

nzaman
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    The friction would cause the whole thing to deorbit. – The Square-Cube Law Oct 18 '18 at 15:15
  • Also if you neutralize the gravity of the hole, you no longer have an accretion disc anyway. – The Square-Cube Law Oct 18 '18 at 15:16
  • @Renan: Neutralise from the perspective of the turbine ring. As one part of the ring begins to spiral in, the other side will be pushed away from the BH. This will be retarded by the accretion disc particles which will try to push it back in, which in turn will push the sinking area out, so on average it stays in place. Naturally, any known material wouldn't survive this kind of cyclic stress, but if you can afford to build a ring of turbines that big, you have the materials technology too. – nzaman Oct 18 '18 at 15:42
  • Imagine a turbine in space. place it in a stream of matter. See, how the passage of said matter causes the fans to rotate. See also, how the matter drags the whole turbine with it, and continuously accelerates it. This decreases the relative speed between turbine and matter, to a point where both have the same speed and therefore the turbine fans stop eventually. Turbines don't work well in space. – M.Herzkamp Oct 19 '18 at 07:21
  • @M.Herzkamp:Unless you have an anchor, which you'll need anyway to transfer the collected energy out.... – nzaman Oct 19 '18 at 07:31
  • On the subject of building a ring shaped structure around a black hole, I invite you to read about Ringworld Instability. Here's the math. The math isn't trivial, but the end result is that a ring around a point-gravity source is inherently unstable. Because gravity gets stronger the closer you get, if one part of the ring dips towards the black hole, the effective force of gravity becomes higher on that part than on the opposing side and it turns into a feedback loop that drags the ring further into the gravity well. You'll need stabilisers. – Ruadhan Oct 19 '18 at 10:26
  • @Ruadhan: Yes you will, because the ring is in the middle of a stream of particles travelling at a sizeable fraction of the speed of light, which is partly stabilised by the ring itself rotating. It also needs anchors outside the stream, which can act as dispersal points for the collected energy. – nzaman Oct 19 '18 at 12:27
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An online comic Schlock Mercenary had a galactic drive engine which harnessed the energy of the spin of the Milky Way to power massive events such as teleporting (terraporting) whole planets and fighting a war with a race of dark matter creatures using the Andromeda galaxy to power their own galactic drive engine to shoot at the Milky Way.

See Pa'anuri

Thorne
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It's kind of simple... but why not just use a big ole pile of antimatter? The use case for the energy is a big burst so you could use any conceivable energy production means to build up your pile, then annihilate an arbitrary amount to power your weapon with a massive energy burst.

0

Dropping things onto a neutron star is another classic approach.

You get about 10% of the rest mass back as energy, as a rule of thumb. (Collecting this energy is problematic, though, as it's largely X-rays and up.)

TLW
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